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125x^2-185x-8=0
a = 125; b = -185; c = -8;
Δ = b2-4ac
Δ = -1852-4·125·(-8)
Δ = 38225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{38225}=\sqrt{25*1529}=\sqrt{25}*\sqrt{1529}=5\sqrt{1529}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-185)-5\sqrt{1529}}{2*125}=\frac{185-5\sqrt{1529}}{250} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-185)+5\sqrt{1529}}{2*125}=\frac{185+5\sqrt{1529}}{250} $
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